question on logarithmz

[mathsboy]

Show that log X^n = n log X.

How would you do that?

[Guest WAVESURFER]

How ironic.

[Trilliam]

carry the one and let them eat cake

[Guest Triple XXX]

[Corrigan]

http://www.youtube.com/watch?v=JrkrTprs0DY

[Skenghis Khan]

why is this place being assaulted by an army of cunts tho,

cant people be permanently ip banned.

[Rippy]

Don't you need to define what logx is

I cba to type it out tbh.

[mathsboy]

Don't you need to define what logx is

I cba to type it out tbh.

why bother replying then. logX is the log function and X is any real number.

[A Bit Better]

Don't you need to define what logx is

I cba to type it out tbh.

why bother replying then. logX is the log function and X is any real number.

LOL. She's right as well.

I swear you can google this sh*t. But I guess that wouldn't get you the attention you crave.

[mathsboy]

Don't you need to define what logx is

I cba to type it out tbh.

why bother replying then. logX is the log function and X is any real number.

LOL. She's right as well.

I swear you can google this sh*t. But I guess that wouldn't get you the attention you crave.

the exponential function is a 1 to 1 function...I will use base e logs.....exp(w) = exp(h) means w = h....thus exp ( ln x^n) = x^n since exp and ln are inverse functions. Now remember that exp(ab) = [exp(a)]^b .....{ more familiar is e^(ab) = [e^(a)]^b }.....so exp( n ln x) = [exp(ln(x))]^n = [ x] ^n , again exp and ln are inverse functions , thus exp[ln (x^n) ] = exp[n ln x] means ln x^n = n ln x, for all real numbers n

http://uk.answers.yahoo.com/question/index?qid=20090504100530AAnxc7j

Do you even understand that mate? dont let me catch you out now.

[Skola]

another crap thread