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Captain Planet

Maths people...

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p(x)=6x³-7x²+1 has factors (x-1) and (2x-1) express p(x) as a product of 3 linear factors.I got (x-1)(2x-1)(3x+1) I'm bare silly. Hence solve the equation:6e³ʸ-7e²ʸ+1=0Should I just rearrange and take ln of each side?Maths is gay :(.

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Factorising the cubic equation gave you a straightforward way to express the exponential function.I think you just substitute x as e(y) in the factorised form[ e(y) - 1 ] [ 2e(y) - 1 ] [ 3e(y) + 1] = 0Equate each part to zero and solve for yDisclaimer: haven't done maths for many a year.

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I'd love to know all this sh*t just for the sake of knowing itBut i really aint got the patience for maths
AgreedIt would be lovely to know.

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Dont think You have to solve for exponential, just e.Basically what superstition said and with my answer.Done deal.

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p(x)=6x³-7x²+1 has factors (x-1) and (2x-1) express p(x) as a product of 3 linear factors.I got (x-1)(2x-1)(3x+1) I'm bare silly. Hence solve the equation:6e³ʸ-7e²ʸ+1=0Should I just rearrange and take ln of each side?Maths is gay :(.
basically had the answer just swap the x for e^yit's really easy to over complicate things in maths

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i understand the

p(x)=6x³-7x²+1 has factors (x-1) and (2x-1) express p(x) as a product of 3 linear factors.
bit but what the f*ck the rest means i have no clue. what are e's and y's in this i completely dont know.ohhhh just clocked. easythe way i had no flipping idea what i was supposed to do with any of that sh*t for about 40seconds >>>>

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sh*t, just reminded me of something I was supposed to do for someone.
wot? how did that remind u? unless u forgot u was supposed to design a quantum accelerator for someone.

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